Webmaster Forum / PHP / Database Access / July 2003

I created a form that inserts the info in the databse. everyhting is fine,
but i would like to have an initial value in the field that when i click on
it it disappear allowing me to add a different value, otherwise, a default
value will be entered.

I have a connection to the database included in the header, the data is
being retireved and displayed properly, just not in the order I want it to.
I want to display the "Orders" header, followed by the table of orders. This
worked fine until I added the News items section, which ...

How can I send radiobuttons by email?This is the form
<form name="name of  form" method="post" action="feedback.php">
 <label>
           <font size="1" face="Verdana, Arial, Helvetica, sans-serif">

how can i crop and image that i already resized?
I created a function that does thumnails. it does a very good job at
resizing jpeg pictures, but no gif's :(
anyhow, when i resize the pictures to a smaller size, i get a black line on

dear Uber Geeks,
Im using an autonumber field in MySQL to serve as a unique identifier for
some data.
As my PHP script inserts data into the database, the ID value is

Hi, i read about the  { } but i do not remember a thing about them, how can
i use and when can i use the curly braces?
thanks, i appreciate any help
Note: of course when it is not in function, like (if else) :)

I have created the following function in my datawriter class in order to
insert values in my test table and return the auto-generated number by
MySQL.  This function suppose to be called and insert values into test table
once at a time.

Does anyone know how to make $rand(0,3) very common, $rand(4,6) rare, and
$rand(7,9) extremely rare and link it to echo one number?
eg:
blah 3-3 blah would be very common or 2-2 or 2-1 etc.

I have a simple table called CD_73 setup with 5 columns. I'm doing a
query on a column looking like this:
+----------+

Thank you for taking the rime to read this post.
I have a mysql db from which I am attempting to join 2 tables by a common ID
and output the result. I've tested the query in phpMyAdmin and it works as
expected but in my page I get this error:

I'm still beginner in PHP! This is my form  and below is the php file.
The email is send perfectly but I don't get the content which is typed in
the form fields when the email is send. can someone give me a hint?
Thanks,

*********************************************************
* This article is posted by an unregistered version of:
* Newsgroup AutoPoster PRO version 1.3.7
*********************************************************

I cannot get a query to work with a string and I can't determine why.
I have two fields to query on, ID and NAME. A query on the ID field
provides results. A query on the NAME field comes up empty but without
an error. It appears the NAME is not being passed.

Can someone help me it really has been a while since I have done any sort of
PHP and even back then I was still learning.
So anyway my problem is that I have the following script which I am trying
to get to work to authorize a username and password then if it's correct

c                echo"<script>"
 . "function openpopup()"
{
 . "var popurl=\"clip.html\""