will <xsl:param name="myParam" select="/.."/> ever have any node

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junkblog747@gmail.com - 27 Nov 2006 19:13 GMT

What will the expression "/.." in the attribute select="/.." return?

I just inherited a huge stylesheet to maintain which has a lot of
parameters such as
<xsl:param name="myParam" select="/.."/>.
And then there is a lot of conditional processing based on this
parameter. I stepped thru the code with a debugger in Oxygen and saw
that the param is always empty (0 nodes selected).

I am trying to figure what the original author of the stylesheet
intended to do. By my reasoning, select="/.." should select the parent
of the root node! And the root node has no parent!
So the parameter myParam will always be empty regardless of the input
xml.

Thanks and Regards
Rohit

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Martin Honnen - 28 Nov 2006 14:23 GMT

> What will the expression "/.." in the attribute select="/.." return?

An empty node-set. That means the default value of that parameter is of
type node-set but it is empty.

> I am trying to figure what the original author of the stylesheet
> intended to do. By my reasoning, select="/.." should select the parent
> of the root node! And the root node has no parent!
> So the parameter myParam will always be empty regardless of the input
> xml.

But if that is a global parameter it can be set to a different value
before a transformation is run.

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Martin Honnen
http://JavaScript.FAQTs.com/

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junkblog747@gmail.com - 28 Nov 2006 17:16 GMT

Thanks for your response.
I guess the original author of the stylesheet forgot to set the value
of the parameters, since he uses the params in if tests.
Thanks and Regards
Rohit

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Webmaster Forum / HTML, CSS, Scripts / CSS / November 2006

will <xsl:param name="myParam" select="/.."/> ever have any node